Análisis de varianza

Análisis de varianza (anova)
- Varianza
- -Hipótesis
- Distribución F (de Fisher)
Dispersión
Parámetros poblacionales
M
Me
Mo 
σ2
σ
x
24
23
21
23
21
20

S2= Σ(xi-X)2/ n-1
12/6- 1 = 2.4
S= 0.48








Estadísticos
X
Me
Mo 
S2
S
X = 22
S2
X1= 2 4
X2= 1 1
X3=-1 1
X4=1 1
X5= -1 1
X6= -2 4

 
 
Días (xi-X) (xi-X)2
37 37 – 35= 2 4  
40 40 – 35 = 5 25
33 33 – 35 = -2 4
20 20 – 35 = -15 225
45 45 – 35 = 10 100
X= 35
S2 = 358/5-1 = 89.5
S = 9.46
Precio  
42.5 -2.58 6.65
44 -1.08 1.16
48 2.92 8.52
46 0.92 0.8464
44.5 -0.58 0.3354
46.9 1.82 3.3124
43.7 -1.38 1.90
X = 45.08  
S2 = 22.7242/ 6 = 3.78 
S = 1.94
 
Observación A B C D X (xi-X) (xi-X)2
1 6 12 11 9 7 7-9 = -2 4
2 9 11 8 7 10 10-9 = 1 1
3 9 10 12 10 10 10-9= 1 1
4 6 8 9 10 9 9-9 = 0 0
5 5 9 10 9 Valores k
X 7 10 10 9 Media de las medias X = 9 Σ = 6
0.05 Nivel de significancia
Estadístico de prueba = F
F = Sb 2/ Sw2
Sb2 = Varianza intermediante
Sb2 = n Σ (xi-Xdoble barra)2 /k – 1 
5 (6) / 4-1 = 10
A (xi-X) (xi-X)2 Σ  
6 6 – 7 = -1 1 14/4 10/4 10/4 6/4
9 9-7 = 2 4
9 9-7 =2 4
6 6-7 = -1 1
5 5-7 = -2 4
Xa = 7 Σ = 14
B  
12 12-10 = 2 4
11 11-10 = 1 1
10 10-10 = 0 0
8 8-10 = -2 4
9 9-10 = -1 1
Xa = 10 Σ = 10
C  
11 11-10 = 1 1
8 8-10 = -2 4
12 12-10 = 2 4
9 9-10 = -1 1
10 10-10 = 0 0
  Σ = 10
D  
9 9-9 = 0 0
7 7-9 = -2 4
10 10-9 = 1 1
10 10-9 = 1 1
9 0
  Σ = 6
Σ = 40/16 = 2.5 
Sw2 = 2.5
F = Sb2 / Sw2 = 10/2.5 = 4
Valor crítico de f = k-1 / 20-4 = 3 / 16 =